50w^2+12w=-8w

Solution for 50w^2+12w=-8w equation:

50w^2+12w=-8w

We move all terms to the left:

50w^2+12w-(-8w)=0

We get rid of parentheses

50w^2+12w+8w=0

We add all the numbers together, and all the variables

50w^2+20w=0

a = 50; b = 20; c = 0;
Δ = b2-4ac
Δ = 202-4·50·0
Δ = 400
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{400}=20$
$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(20)-20}{2*50}=\frac{-40}{100}
=-2/5
$
$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(20)+20}{2*50}=\frac{0}{100}
=0
$